someone help me please
Attachments:
Answers
Answered by
2
hello...
cosA ( 1 + sinA) +cos A 1-sinA ) / 1 - sin ^2
= 2 cosA /( 1-sin ^2 )
= 2 / cos A
= cos A = 2 /4
= cos A = 1 / 2
cosA = cos 60
A = 60 degree...
I hope it help you...
please mark it as a brainieist answer.......
cosA ( 1 + sinA) +cos A 1-sinA ) / 1 - sin ^2
= 2 cosA /( 1-sin ^2 )
= 2 / cos A
= cos A = 2 /4
= cos A = 1 / 2
cosA = cos 60
A = 60 degree...
I hope it help you...
please mark it as a brainieist answer.......
Aasthakatheriya1:
dont know
Answered by
3
cos0/1-sin0+cos0/1+sin0=4
cos0{1/1-sin0+1/1+sin0}= 4
cos0{1+sin0+1-sin0/(1-sin0)(1+sin0}=4
cos0{2/1-sin^2 0}= 4
cos0{2/cos^2 0} =4
2/cos0 =4
cos0= 2/4=1/2
cos0=cos 60
0=60 ans....
hope it helps you........
cos0{1/1-sin0+1/1+sin0}= 4
cos0{1+sin0+1-sin0/(1-sin0)(1+sin0}=4
cos0{2/1-sin^2 0}= 4
cos0{2/cos^2 0} =4
2/cos0 =4
cos0= 2/4=1/2
cos0=cos 60
0=60 ans....
hope it helps you........
Similar questions