Question

Someone please answer these questions of maths ncert class 8 chapter 11 mensuration page 176(Try These)​

Answer 1

Answer:

Hope this will help you........ Last one is same as second.

Step-by-step explanation:

Answer 2

31.75  cm² is area of the figure

Step-by-step explanation:

Area of ΔMAN +  Area of trapezium ACON + Area of Δ COP  + Area of ΔMBR + area of Trapezium BRQD + area of Δ PDQ

Area of ΔMAN  = (1/2)MA * AN = (1/2) * 2 * 2.5  = ccm²

AC = MC - MA = 6 - 2 = 4 cm

Area of trapezium ACON  = (1/2)(AN + CO)*AC = (1/2)(2.5 + 3)*(4) = 11  cm²

CP = MP - MC = 9 - 6 = 3

Area of Δ COP = (1/2)CP * OC = (1/2)* 3* 3  = 4.5 cm²

Area of ΔMBR = (1/2)MB * BR = (1/2) * 4 * 2.5  = 5 cm²

BD = MD - MB = 7 -4 = 3

area of Trapezium BRQD = (1/2)(BR + QD)*BD  = (1/2) (2.5 + 2)*3  = 6.75 cm²

DP = MP - MD = 9 - 7 = 2

area of Δ PDQ = (1/) * PD * DQ = (1/2)*2 * 2 = 2 cm²

Area = 2.5 + 11 + 4.5 + 5 + 6.75 + 2

= 31.75  cm²

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