Question

someone please help me out with this question

Answer 1

Explanation:

$\large{\underline{\underline{\mathfrak{Given:-}}}}</p><p>$

Circuit

$\large{\underline{\underline{\mathfrak{To\:Find:-}}}}$

• Total resistance
• Total current
• Readings in Ammeter

$\large{\underline{\underline{\mathfrak{Solution:-}}}}$

At the above of the circuit we are given 2 parallel resisters of 2Ω

$\large{\boxed{\mathsf{ \frac{1}{R_a} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} .... }}}</p><p>$

\

$\large\frac{1}{R_a}= \frac{1}{2Ω}+ \frac{1}{2Ω}$

$\large\frac{1}{R_a}= \frac{4Ω}{4Ω}$

$\large {R_a}= 1Ω$

At below of the circuit we have 3 resistors in parallel of 2Ω let's call it Rb

$\large\frac{1}{R_b}=\frac{1}{2Ω} + \frac{1}{2Ω} + \frac{1}{2Ω}$

by solving this we get,

$\large R_b= \frac{2}{3}Ω$

Now, Ra and Rb are in parallel So by solving these we get

Total resistance as

2/5Ω

$\large{\underline{\underline{\mathfrak{By\: Ohm's\: law:-}}}}</p><p>$

V=IR

I= V/R

I=10÷2/5

I=10×5/2

I= 25A