Math, asked by pranaysingh29pc9qh6, 11 months ago

Someone please help me to do this question

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Answered by hajafai01faiz

1

Answer:

sin2(n+1)A - sin2nA = sin(2n+1)A.sinA

we have formula sin2a - sin2b =sin(a-b)sin(a+b)

therefore

sin2(n+1)A - sin2nA=sin[(n+1)A+nA].sin[(n+1)A-nA]

=sin(2n+1)A.sinA =RHS

hence proved

mark as brainliest plz

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