Question

SOMEONE PLEASE HELP ME WITH THIS QUESTION FAST
A is twice old as B.Five years ago,A was 3 times as old as B.Find their present ages.

Answer 1

Step-by-step explanation:

Let the present age of B be x

then age of A =2*x

5 years ago age of B was =x-5

ATQ age of A before 5 years3(x-5)

so 2x-5=3x-15

=2x-3x=-15+5

=-x=-10

=x=10

so present age of B=10 years

and present age of A=2*10=20 years

Answer 2

Step-by-step explanation:

let age of A be x and age of B be y

By first condition:

x=2y

five years ago there age was x-5 and y-5

by second condition:

x-5=3(y-5)

x-5=3y-15

x-3y=-15+5=-10

but x=2y

therefore , 2y-3y=-10

-y = -10

y=10

x=2(10)=20

there present ages are 20 and 10 respectively

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