Question

someone please helpppp

Answer 1

hi friend,

the. correct option is →D

which is a=c^b/c

now given ,

=>10^(log base a(log base b(log x base c))=1

applying logarithm on both sides, we get

=>log 1 base 10=(log base a(log base b(log x base c))

=>0=(log base a(log base b(log x base c)

so,to satisfy this condition,

=>(log base b(log x base c) =1

converting into exponential form

=>b=logx base c

again converting into exponential for

=>c^b=x-------(1)

and also given 10^(log base b(log base c(logx base a))=1

applying logarithm on both sides, we get

=>log 1 base 10=log base b(log base c(logx base a))

=>0=log base b(log base c(logx base a))
so,to satisfy this condition,

=>(log base c(logx base a)) =1
converting into exponential form

=>logx base a=c

again,
converting into exponential form

we get

=>x=a^c

by (1)

=>a^c=c^b

=>a=c^(b/c)

I think it is little confusing...but still I hope it will help u :)