someone please helpppp....
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we know that x+1/x = 7
Squaring both side ,
x^2+1/x^2 + 2*x*1x=49
{we know (a+b)^2 = a^2+b^2+2ab}
x^2 + 1/x^2 + 2 =49
x^2+1/x^2=47. -(1)
(x-1/x)^2=x^2 + 1/x^2 -2*x*1/x
(x-1/x)^2=47-2. { By using (1)}
(x-1/x)^2=45
square rooting both sides,
x-1/x = 3√5
bhabna75:
thanks
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