Math, asked by asthamishra214, 9 months ago

someone pls solve this only the person who can solve this will only answer okk others shut up
find the point one the x_ axis which is equidistant from the points (2,-5) & (-2,9)....

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Answered by Anonymous

4

the locus of points equidistant from the given points is : 2x - 7y + 14 =0

and the point which is on x axis is (-7,0)

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