someone solve this pls
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Step-by-step explanation:
x ^ -(a² - ab - ac + bc) x ^ -(b² - bc - ba + ac) x ^ -(c² - ac - bc + ab) = 1
∵ xⁿ × xⁱ = x ⁿ⁺ⁱ
∵ x -(a² + b² + c² - ab - bc - ac) = 1
∵ xⁿ = 1 implies n = 0
∴ (a² + b² + c² - ab - bc - ac) = 0
And this equation has multiple triplet solutions for (a , b , c)
The line representing the solutons to this equation is attached in the answer itself.
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