Math, asked by AkshithaZayn, 1 year ago

Sorry for the mistake in previous question.

Factorise :

9x {}^{2} y - 24xy {}^{2}  + 16y {}^{3}
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Answers

Answered by Anonymous
8
Hola there..

Given

=> 9x²y - 24xy² + 16y³

=> 9x²y - 12xy² - 12xy² + 16y³

=> 3xy(3x - 4y) - 4y²(3x - 4y)

=> (3x - 4y)(3xy - 4y²)

=> (3x - 4y)y(3x - 4y)

=> y(3x - 4y)². ....Ans

Hope this helps....:)

AkshithaZayn: so, splitting the middle term is used. right?can we do it by any identity?
Anonymous: yes we can do it by other ways also
AkshithaZayn: It's correct ans :)
Anonymous: thx. for correcting me.
Answered by ArchitectSethRollins
11
Hi friend
---------------
Your answer
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★ FACTORISATION
-------------------------------

9x²y - 24xy + 16y³

Now ,
---------

Taking y common from the three terms , we get,

y(9x² - 24xy + 16y²)

Now, we can factorise by splitting the middle term.

y(9x² - 12xy - 12xy + 16y²)

=> y[3x(3x - 4y) - 4y(3x - 4y)]

=> y(3x - 4y)(3x - 4y)

=> y(3x - 4y)²

Alternately : -

We can solve by using the identity => (a - b)² = a² - 2ab + b².

=> y(9x² - 24xy + 16y²)

=> y[(3x)² - 2 × (3x) × (4y) + (4y)²]

=> y(3x - 4y)²

HOPE IT HELPS

ArchitectSethRollins: aksi was this 10th class sum?
AkshithaZayn: nah. 8th ;p
AkshithaZayn: jus to know :)
ArchitectSethRollins: :sob: i thought you gave a sum from your 10th textbook
AkshithaZayn: ;p
Anonymous: such type of easy sums can't be in class 10 th
Anonymous: hahaha
AkshithaZayn: Yup ;p (sometimes, I cant to get simple questions) ;p
ArchitectSethRollins: ;)
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