Math, asked by Mister360, 2 months ago

Sorry my latest question was wrong.
correct question
If volume of cylinder is 616 cu. cm and height is 4 cm. Then find radius and circumference of base

Answers

Answered by CopyThat
14

Answer:

  • Radius of cylinder = 7 cm
  • Circumference of the base of cylinder = 44 cm

Step-by-step explanation:

Given

  • Volume of cylinder = 616 cm³
  • Height of cylinder = 4 cm

To find

  • Radius of cylinder
  • Circumference of base

Solution

  • Volume of cylinder = πr²h
  • 616 = 22/7 × r² × 4
  • 616 × 7/22 = 4r²
  • 196 = 4r²
  • r² = 196/4
  • r² = 49
  • r = 7

Verification

  • Volume = πr²h
  • 616 = 22/7 × 7 × 7 × 4
  • 616 = 22 × 28
  • 616 = 616
  • L.H.S = R.H.S

Hence, the radius of cylinder is 7 cm.

  • Circumference of base of cylinder = 2πr
  • Circumference of base of cylinder = 2 × 22/7 × 7
  • Circumference of base of cylinder = 44/7 × 7
  • Circumference of base of cylinder = 44

Hence, the circumference of base of cylinder is 44 cm.

Answered by Anonymous
64

\large \mathfrak \purple {➨ \:  \: Question \: :-}

If volume of cylinder is \sf 616cm^3 and height is 4cm, find the radius and circumference of the base.

 \\

\large \mathfrak \purple {➨ \:  \: Solution \: :-}

Given that :-

  • Height of cylinder = 4cm
  • Volume of cylinder = \sf 616cm^3

Finding the radius :-

\boxed {\bf \blue {\bigstar  \: \: Volume \: of \: cylinder=\pi r^2h  \: \: \bigstar}}

\blue ➨ \:  \: \sf  \cfrac{22}{7} (r)^2(4) = 616

\blue ➨ \:  \: \sf  22 \times  {r}^{2}  \times 4 =  616 \times 7

\blue ➨ \:  \: \sf r^2 \times 88 = 4312

\blue ➨ \:  \: \sf r^2= \cfrac{4312}{88}

\blue ➨ \:  \: \sf r=7cm

\bf \blue {\therefore \: Radius \: of \: the \: cylinder =7cm }

Verifying the radius value :-

Substituting the values and solving :-

\blue ➨~~\sf \pi r^2h=616cm^3

\blue ➨~~\sf \cfrac{22}{7}(7)^2(4)=616cm^3

\blue ➨~~\sf \cfrac {22}{\cancel 7} \times (\cancel 7)(7)(4)=616cm^3

\blue ➨~~\sf 22 \times 7 \times 4=616cm^3

\blue ➨~~\sf 616cm^3=616cm^3

\bf \blue {\therefore~Verified!}

Finding circumference of the base :-

\boxed {\bf \blue{\bigstar~~ Circumference \: of \: circle=2\pi r ~~\bigstar} }

\blue ➨ \:  \: \sf 2( \cfrac{22}{7} )(7)

\blue ➨ \:  \: \sf 2( \dfrac{22}{\cancel7} )(\cancel7)

\blue ➨ \:  \: \sf 44cm

\bf \blue {\therefore \: Circumference \: of  \: base=44cm}

 \\

\large \mathfrak \purple {➨ \:  \: Know \: more \: :-}

  • Area of circle = \sf \pi r^2
  • Radius of circle = \sf \cfrac {Diameter}{2}
  • Area of semicircle = \sf \cfrac {\pi r^2}{2}
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