Soumya leaves for her office from her house. She walks towards east. After moving a distance of 20m, she turns south and walks 10m. Then she walks 35m towards the west and further 5m towards the north. She then turns towards east and walks 15m. What is the straight distance between her initial and final positions?
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From A to G, total distance is →
AG=AD−GD
Here, AD=BC=10m & GD=EF=5M
∴ AG=10−5=5m
Hence, the straight distance between the initial and final positions of Soumya is 5m.
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