South african cricket captain lost the toss of a coin 13times out of 14.chances of this happening was? a.7/2^13 b.1/2^13 c.13/2^14 d.13/2^13
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tossing of a coin has only two outcomes which are equally likely hence it obviously follow binomial distribution
Let x be chances that he lost 13 times out of 14
where,p=probability=1/2
q=1-p=1-1/2=1/2,n=14
hence,p(X=x)=n(xp^x q^n-x)
=14c13(1/2)^13(1/2)^14-13
=14!/13!
1/2^13 1/2
=14×1/2^13×1/2
=7/2^13
Let x be chances that he lost 13 times out of 14
where,p=probability=1/2
q=1-p=1-1/2=1/2,n=14
hence,p(X=x)=n(xp^x q^n-x)
=14c13(1/2)^13(1/2)^14-13
=14!/13!
1/2^13 1/2
=14×1/2^13×1/2
=7/2^13
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