Math, asked by vij9, 5 months ago

sovle fastt for point???? ​

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Answered by BrainlyEmpire
71

\sf\large\underline\green{Let:-}

\sf{\implies The\: length\:_{(playground)}=x}

\sf{\implies The\: breadth\:_{(playground)}=y}

\sf\large\underline\green{Given:-}

\sf{\implies Area\:_{(playground)}=420\:m^2}

\sf\large\underline\green{To\: Find:-}

\sf{\implies The\: dimensions\:_{(playground)}=?}

\sf\large\underline\green{Solution:-}

To calculate the dimensions of rectangular playground , at first we have to set up equation as per the given Question by applying formula. Then solve those equation after that you get the value of x and y where x is length of playground and y is the breadth of playground.

\sf\small\underline\blue{Calculation\: for\: first\: equation:-}

\tt{\implies Area\:_{(playground)}=length*breadth}

\tt{\implies x*y=420}

\tt{\implies x=\dfrac{420}{y}------(i)}

\sf\small\underline\blue{Calculation\: for\:second\: equation:-}

\tt{\implies Length\:_{(increased\:by\:7)}*breadth\:_{(decreased\:by\:5)}=Area\:_{(remain\: same)}}

\tt{\implies (x+7)*(y-5)=x*y}

\tt{\implies xy-5x+7y-35=xy}

\tt{\implies -5x+7y=35-----(ii)}

In eq (ii) putting the value of x=420/y :-]

\tt{\implies -5*\dfrac{420}{y}+7y=35}

\tt{\implies \dfrac{-2100}{y}+7y=35}

\tt{\implies \dfrac{-2100+7y^2}{y}=35}

\tt{\implies 7y^2-35y-2100=0}

Here dividing by 7 on both sides:-]

\tt{\implies y^2-5y-300=0}

Now splitting the middle term here:-]

\tt{\implies y^2-20y+15y-300=0}

\tt{\implies y(y-20)+15(y-20)}

\tt{\implies (y+15)(y-20)=0}

\tt{\implies \therefore\:y=-15\:\:,20}

Here negative values can't be the dimensions of rectangle so, we take y=20 here:-]

\tt{\implies breadth\:_{(playground)}=20m}

Now putting the value of y=20 in eq (i) :-]

\tt{\implies x=\dfrac{420}{y}}

\tt{\implies x=\dfrac{420}{20}}

\tt{\implies x=21m}

\sf\large{Hence,}

\sf{\implies The\: length\:_{(playground)}=21\:m}

\sf{\implies The\: breadth\:_{(playground)}=20\:m}

Answered by Anonymous
1

refer the attachment ;)

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