Question

spam if u are a loser....
all the 3...​

Answer 1

Explanation:

11) Focal Lenght ,(f) = -15

Distance of image (V) = -10

$\frac{1}{v} - \frac{1}{v} = \frac{1}{f}$

1/u = -(1/10) - (1/-15)

1/u = 1/5 - 1/10

1/u = -0.333

U = -30 Cm.

So, the Object is placed 30Cm. away from the Concave lense.

12 ) Given that

u= -10 cm

f= 15 cm

We need to find v

We know the formula

1/f = 1/v + 1/u

Therefore, 1/v= 1/f – 1/u

Substituting the known values in the above equation we get,

1/v= 1/15 + 1/10

1/v = (2+3)/30 (lcm)

Hencev=5/30 = 6 cm

v= 6cm

13) Magnification = height of the image/height of the object = distance of the image/distance of the object. The magnification produced by a plane mirror is +1 means then the size of the image is equal to the size of the object. If m has a magnitude greater than 1 the image is larger than the object, and an m with a magnitude less than 1 means the image is smaller than the object.

Answer 2

Answer:

Focal Lenght ,(f) = -15

Distance of image (V) = -10

\frac{1}{v} - \frac{1}{v} = \frac{1}{f}

v

1

−

v

1

=

f

1

1/u = -(1/10) - (1/-15)

1/u = 1/5 - 1/10

1/u = -0.333

U = -30 Cm.

So, the Object is placed 30Cm. away from the Concave lense.

12 ) Given that

u= -10 cm

f= 15 cm

We need to find v

We know the formula

1/f = 1/v + 1/u

Therefore, 1/v= 1/f – 1/u

Substituting the known values in the above equation we get,

1/v= 1/15 + 1/10

1/v = (2+3)/30 (lcm)

Hencev=5/30 = 6 cm

v= 6cm

13) Magnification = height of the image/height of the object = distance of the image/distance of the object. The magnification produced by a plane mirror is +1 means then the size of the image is equal to the size of the object. If m has a magnitude greater than 1 the image is larger than the object, and an m with a magnitude less than 1 means the image is smaller than the object.