Special Product i.(x-3) (x-6)
ii.(p-3) (p+2)
iii.(4+b) (4-b)
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I'm not understand sorry I will give answer in next time
Answered by
1
Answer:
IT'S i) (x-3)(x-6)
=x^2-6x-3x+18
=x^2-9x+18.
ii) (p-3)(p+2)
=p^2+2p-3p-6
=p^2-p-6.
iii) (4+b)(4-b)
= 4^2-b^2
=16-b^2.
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