Math, asked by anshsirat, 11 months ago

Special Product i.(x-3) (x-6)
ii.(p-3) (p+2)
iii.(4+b) (4-b)​

Answers

Answered by missyashika03
1

Answer:

I'm not understand sorry I will give answer in next time

Answered by happiness10
1

Answer:

IT'S i) (x-3)(x-6)

=x^2-6x-3x+18

=x^2-9x+18.

ii) (p-3)(p+2)

=p^2+2p-3p-6

=p^2-p-6.

iii) (4+b)(4-b)

= 4^2-b^2

=16-b^2.

HOPE THIS WILL HELP YOU.

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