Question

specific resistance of aluminum is 2.65×10^-8 ohm meter. find the resistance of an aluminum wire of length 100meter & diameter 1mm.​

Answer 1

Answer:

The resistance is given as

R=pL/A

Here

P = 2.6 x 10^-8 ohm-m

L = 60 cm = 0.6m

A = mm^2 = 10^-6 m^2

So we have

R = ( 2.6×10^-8×0.6)/10^-6

Thus

R = 1.56 × 10^-2 ohms