Question

speed of a bus is 20% more than that of a car. both the bus and the car strat from a point P and reach a point Q at the same time, Q being 100km away from P. on the way, the bus loses approximately 5min while stopping at a station. Wt is the speed of the car?​

Answer 1

Answer:

Let the speed of car= SSo speed of Train = 1.2STime taken by car to travel 180Km=180/S.Since the train stopped for 30- minutes, ie., 0.5 hours.The train travelled for=(180/S-0.5) hoursSpeed x Time= Distance travelled . So (180/S - 0.5) x 1.2 S= 180On simplification we get216-0.6S=180.So 0.6S=36; or S= 60Km/ hSpeed of car= 60Km/h

Therefore speed of train= 60 x 1.2 =72 Km/ h

Answer 2

Given :

Distance between P and Q = 100 km

Speed of bus = 20 % more than that of car

To find:

Speed of car

Solution:

Let us take the speed of the car as X and the speed of the bus as Y.

Speed of bus ( Y ) = 20 % more than speed of car

Y = X + (20/100) X

Y = (120/100) X

Y = ( 6/5 ) X

As, Speed = Distance / time

From here,

Time taken by car ( t₁ ) = ( 100 / X) Hours

Time taken by bus ( t₂ ) =  $\frac{500}{6 X}$ Hours = $\frac{250}{3X}$ Hours

Since, both the vehicles reach point Q at the same time with bus losing additional 5 minutes (i.e. 1/12 hours) while stopping at the station,

the equation for both the bus and car can be written as,

$\frac{100}{X}$ = $\frac{250}{3 X}$ + $\frac{1}{12}$

X = 200 km per hour

Hence the speed of the card is 200 km/h