Question

Speed ​​of induction motor 1000rpm frequency is 58 and 6 are what will be the slip of the motor?

Answer 1

Induction Motor,

Speed Ns=( 120* frequency)/(No.of poles)

Speed Ns= (120*50)/6=1000 rpm.

Given that,

Full load speed N=950 rpm.

So the slip S= (Ns-N)/Ns —————-(1)

=(1000–950)/1000

Slip at Full load S fl=0.05

Since slip is directly proportional to slip, At half full load,Slip also becomes half.

Slip at Half full load Shl= 0.05/2=0.025

From equation 1,

So the speed at half full load N = Ns(1-S)

N= 1000(1–0.025)

=975 rpm.

The speed at half full load is 975 rpm.