Speed of light in S.I. system is 3 * 108 m/s. In a
new system, unit of length is a km and unit of
time is b second. Then speed of light in new
system of unit is
b
(1)
5.105
(2)
105
a
3a
3a
3b
(3)
.105
(4)
105
b
a
Answers
Answered by
1
Answer:
3×10^5×b/a
Explanation:
Speed of Light in SI system = 3 × 10^8 m/sec
Light covers a distance of 3 × 10^8 m in 1 sec
Therefore,
It covers in 1 sec
\frac{3 \times {10}^{8} }{a \times {10}^{3} } km
a×10
3
3×10
8
km
Hence it covers
in b sec
3 \times {10}^{5} \times \frac{b}{a}3×10
5
×
a
b
Answered by
0
Answer:
3×10^5×b/a
Explanation:
Speed of Light in SI system = 3 × 10^8 m/sec
Light covers a distance of 3 × 10^8 m in 1 sec
Therefore,
It covers in 1 sec
\frac{3 \times {10}^{8} }{a \times {10}^{3} } km
a×10
3
3×10
8
km
Hence it covers
in b sec
3 \times {10}^{5} \times \frac{b}{a}3×10
5
×
a
b
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