Question

Speed of sound in air is 300 m/s. The distance between two successive nodes of a stationary

wave of frequency 1000 Hz is _______.

(A) 10 cm (B) 20 cm (C) 15 cm (D) 30 cm

Answer 1

D. 300/1000=0.3x100=30cm

Answer 2

The distance between two successive nodes of a stationary  wave is 30 cm.

Explanation:

Given that,

Speed of sound in air is 300 m/s.

Frequency of wave, f = 1000 Hz

We need to find the distance between two successive nodes of a stationary  wave. The speed of a wave is given by :

$v=f\lambda$

$\lambda=\dfrac{v}{f}$

$\lambda=\dfrac{300}{1000}$

$\lambda=0.3\ m$

or

$\lambda=30\ cm$

So, the distance between two successive nodes of a stationary  wave is 30 cm. Hence, this is the required solution.

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