Question

speed of the car is reduced from 90km/hr to 36km/hr in 5s what is the distance travelled by the car in this time interval

Answer 1

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Answer 2

u:-90km/h
v:-36km/h
t:-5s=.083hr

a=v-u÷t
=90-36÷.083
=-343.73m/s×s

s=ut+.5at×t
=