Question

Speeds of Boat A and B in still water are in the ratio of 3:2 Rate of current is 10 Km/hr. Both Boats started from Point P to point Q downstream at the same time. After Boat B reaching Point Q, in return journey, it is powered by engine due to which the speed of the boat in still water is increased by 70%, while retuned Boat A returned to Point Q as usual. Both the boats returned back to point P at the same time. Then what is the speed of Boat A?​

Answer 1

Answer:

Step-by-step explanation:

S 1 /S 2 = 3/2

R = 10

then

(1/3x+10)+ (1/3x-10) = (1/2x+10) + (1/3.4x-10)

x = 10

Speed of boat A =3*10 = 30

30 Km/hr