Question

sperical ball of lead 3 cm in diameter is melted and recast into three sperical balls in diameter of two of these poles are was 1 cm and 1.5 cm find the diameter of the third ball

Answer 1

Answer:

volume of spherical  ball = volume of  poles

Radius of sperical ball = 1.5 cm , radius r1 of spherical poles = 0.5 , radius r2 of spherical poles = 15/20 ==> 3/4 ==> 0.75

4/3πR³ = 4/3π×(r1)³ + 4/3π×(r2)³ + 4/3π×(r3)3

4/3π(1.5)³ = 4/3π[(0.5)³+ (0.75)³ + (r3)³]

(1.5)³ = (0.5)³+(0.75)³+(r3)³

==> 3.375 = 0.125 + 0.421875 + (r3)³

==> 3.375-0.125-0.421875 = (r)³

==> √2.828125 = r

==> 1.681 = r

diameter = 2×1.681 ==> 3.362 (approx.)