Question

Sphere of radius 15 cm moving with a uniform velocity of 2 m/s throug a liquid of specific gravity 0.9 anf dynamic viscosity 0.8 poise the reynolds number will beh

Answer 1

Hii Dear,

◆ Answer -

Reynolds number = 675

● Explaination -

# Given -

r = 15 cm = 0.15 m

v = 2 m/s

μ = 0.8 poise

ρ = 0.9×1000 = 900 kg/m^3

# Solution -

Reynold's number is calculated by -

R = 2.ρ.v.r / μ

R = 2 × 900 × 2 × 0.15 / 0.8

R = 675

Therefore, Reynolds number iz 675.

Thanks dear...