Math, asked by Bose9426, 1 year ago

Spherical Marbles of diameter 1.4 cm. are dropped into a cylindrical beaker of diameter 7 cm., which contains some water. Find the number of marbles that should be dropped in to the beaker, so that water level rises by 5.6 cm.

Answers

Answered by mysticd
473
Hi ,

Diameter of the Spherical ball ( d ) = 1.4cm

radius of the ball ( r ) = d/2

r = 0.7 cm

Volume of the Sphere = ( 4/3 )πr³ cm³

v = ( 4/3 ) π ( 0.7 )³ ----( 1 )

ii ) Diameter of the cylinder ( D ) = 7cm

radius of the cylinder ( R ) = D/2

R = 7/2 cm

Suppose water level rises by h= 5.6 cm

in the cylindrical beacker .

Then ,

Volume of the cylinder of height

h = 5.6 cm and radius 7/2 cm

V = πR²h

V = [ π ×( 7/2 )² × 5.6 ]cm³ ----( 2 )

Let the number of balls dropped in the

beaker = n

n = V /v

n = [π ×(7/2)²×5.6cm³]/ [4/3×π×(0.7)³cm³]

after cancellation ,we get

n = 150

I hope this helps you.

: )

Answered by sunitach2981
297

Hope it helps uuuu..

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