Question

Split 69 into 3 parts such that they are in A.P. and product of the two smaller parts is 48

Answer 1

let the parts. be a-d, a, a+d
Now (a-d) +a+a+d=69
3a=69
a,=23
Now product of smaller parts =a(a-d) =48
23(23-d)=48
solve for d.. and put in numbers. taken

Answer 2

Let the three terms be a-d, a, a+d
a-d+a+a+d=69
3a=69
a=23
(a-d)a=48
a²-ad=48
23-d=48/23
d=23-48/23=20.91
Then the sequence is (23-20.91),(23),(23+20.91)=2.09, 23, 43.91