Split 69 into three parts such that they are in A.P and the product of the smaller and the largest part is 493.
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Let the first term of the AP be 'a'
And the common difference be 'd'
Since 69 split into 3 parts such that they form an AP.
Let the three parts be (a - d), (a) and (a + d).
Therefore,
(a - d) + (a) + (a + d) = 69
3a = 69
a = 23
The product if two smaller parts = 483
So,
(a) × (a - d) = 483
23 × (23 - d) = 483
⇒ 529 - 23d = 483
⇒ - 23d = 483 - 529
⇒ - 23 d = - 46
⇒ d = 46/23
⇒ d = 2
Therefore,
The 3 parts are
23 - 2 = 21 ;
23
and 23 + 2 = 25
Hence the parts of the given AP are 21, 23, 25
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