Split the middle term
4x^2 + 87x + 125
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Answer:
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Step-by-step explanation:
4x2 + 87x + 125 = 0
using the Quadratic Formula where
a = 4, b = 87, and c = 125
x= −b ± b2 − 4ac−−−−−−−√2a
x=−87 ± 872 − 4(4)(125)−−−−−−−−−−−−√2(4)
x= −87 ± 7569 − 2000−−−−−−−−−−√8
x= −87 ± 5569−−−−√8
The discriminant b2 − 4ac > 0
so, there are two real roots.
Cannot Simplify the Radical:
x = −87 ± 5569−−−−√8
x = −878 ± 5569−−−−√8
Simplify fractions and/or signs:
x = −878 ± 5569−−−−√8
which becomes x = −1.54678
x = −20.2032
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