Question

split the middle term 6s^2-3-7x​

Answer 1

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Here is your answer....

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6s²-2-3-7x

Final result :

(2x - 3) • (3x + 1)

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

Step by step solution :

Step 1 : Equation at the end of step 1 :

((2•3x2) - 3) - 7x

Step 2 : Trying to factor by splitting the middle term

2.1 Factoring 6x2-7x-3

The first term is, 6x2 its coefficient is 6 .

The middle term is, -7x its coefficient is -7 .

The last term, "the constant", is -3

Step-1 : Multiply the coefficient of the first term by the constant 6 • -3 = -18

Step-2 : Find two factors of -18 whose sum equals the coefficient of the middle term, which is -7 .

-18 + 1 = -17

-9 + 2 = -7 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and 2

6x2 - 9x + 2x - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

3x • (2x-3)

Add up the last 2 terms, pulling out common factors :

1 • (2x-3)

Step-5 : Add up the four terms of step 4 :

(3x+1) • (2x-3)

Which is the desired factorization

Final result :

(2x - 3) • (3x + 1)

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Answer 2

Answer:

Here is your answer...

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