Question

splitting the middle term 2x^2-17-30​

Answer 1

Answer:

$\boxed{(2x + 5) (x - 6)}$

Step-by-step explanation:

Your question has a mistake, so your correct question is :

$\large\implies\mathtt{2x^2-17x-30}$

Here, we can find out that there are not any factors of 30 which can make 17.

As we know, our coefficient should always be 1 so we have to multiply 2 with 30. Then, we got 60.

Do the prime factorization of 60, you'll get two numbers : 12 and 5 which can add up to 17.

$\large\longrightarrow\mathtt{2x^2-12x-5x-30}$

$\large\longrightarrow\mathtt{2x(x-6) + 5(x-6)}$

Hence, we got our answer :

$\large\longrightarrow\mathtt{(2x+5)(x-6)}$

___________________________

Answer 2

Correct question :

Splitting the middle term : 2x² - 17x - 30

Answer :

(2x + 5) (x - 6)

Explaination :

1) Find the product of 1st and last term

=> 2 × 30 = 60

2) Find the factors of 60 in such way that addition or subtraction of that factors is the middle term ( here middle term is - 17x)

=> 12 × 5 = 60

=> - 12 + (-5) = - 17

Now,

=> 2x² - 17x - 30

=> 2x² - 12x - 5x - 30

=> 2x (x - 6) + 5 (x - 6)

=> (2x + 5) (x - 6)