Question

Spring balance is of least count 2 GF its pointer is at three division below the zero mark when no weight is suspended from it but when a stone is suspended from it the reading becomes 48 GF . When the same suspended force is immersed in water the reading become 40 GF calculate the actual weight of stone in air and the Apparent loss and weight of the stone when immersed in water

Answer 1

Least count 2gf means each division 2gf

Given 3division below zero means 6gf(spring balance below means positive)

When stone suspended the reading comes to 48gf but 6gf is already extra so actual wt of stone 48-6=42gf

And apparent loss =48-40=8gf

I don't assure my answer