Question

Spring constant of spring which has potential energy of 50 J when it is stretched through a distance of 10cm is

Answer 1

here k=?
p.E=50j
x=10cm
p.E= -kx
50= -k×10
5= k

Answer 2

The potential energy of a certain spring when stretched through a distance S is 10J The amount of work that must be done on this spring to stretch it through an additional distance S will be a) 30J b)40J c) 10J d) 20 J.plz.answer fast.... ... The answer will be 30 j (a) ,I think so I ..