sqareroot x/y + squareroot y/× = 10/3 find xy
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Hi ...dear...
here is your answer!!!
....(√x/√y)+(√y/√x)=10/3
(√x²+√y²)/√xy =10/3
10√xy = 3(x+y)
100xy =9(x+y)²
100xy =9x²+18xy+9y²
82xy=9(x²+y²)
xy=9(x²+y²)/82
..but unfortunately.......
xy is neither constant nor unique for any (x, y) pairs .....
Are you sure your question is correct?...
.
see picture
hope this helps you....
Regards Brainly Star Community
#shubhendu
here is your answer!!!
....(√x/√y)+(√y/√x)=10/3
(√x²+√y²)/√xy =10/3
10√xy = 3(x+y)
100xy =9(x+y)²
100xy =9x²+18xy+9y²
82xy=9(x²+y²)
xy=9(x²+y²)/82
..but unfortunately.......
xy is neither constant nor unique for any (x, y) pairs .....
Are you sure your question is correct?...
.
see picture
hope this helps you....
Regards Brainly Star Community
#shubhendu
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abhishek3786kupa3aco:
wrong
listen it is impossible to find xy using this equation
i solve this equation and change it in form of x/y ...if we can also able to find xy using This equation...it meant that we can also find the values of x and y by multiplying equations.....and it is impossible to find values of x and y using one equation!!!!
hope you understood
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0
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