sqaure root of the 8836
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indiankhiladi
Secondary School Math 5+3 pts
3root+2root by 3root-2 root
Report by Puneet85 23.05.2018
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rRishita1
RRishita1English Shakespeare
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√3 + √2 / √3 - √2
= (√3 + √2 / √3 - √2 ) × ( √3 + √2 / √3 + √2)
= (√3 + √2)^2 / (√3)^2 - (√2)^2
= [ (√3)^2 + (√2)^2 + 2×√3×√2 ] / 3-2
= 3 + 2 + 2√6 / 1
= 5 + 2√6
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