Question

( \sqrt [ 3 ] { 7 } ) ^ { 6 }​

Answer 1

Answer:

1 Rationalize the denominator: \frac{\sqrt{3}}{\sqrt{7+\sqrt{5}}} \cdot \frac{\sqrt{7+\sqrt{5}}}{\sqrt{7+\sqrt{5}}}=\frac{\sqrt{3}\sqrt{7+\sqrt{5}}}{7+\sqrt{5}}