Sqrt(6+2sqrt(3)+2sqrt(2)+2sqrt(6)
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Step-by-step explanation:
Given: (√6+2√2)(4√6−3√2).
Use the FOIL theorem, which states that (a+b)(c+d)=ac+ad+bc+bd.
So, we get:
=√6⋅4√6−3√2⋅√6+2√2⋅4√6−2√2⋅3√2
=4⋅6−3√12+8√12−6⋅2
=24−12+5√12
=12+5√12
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