Math, asked by shaimakagdi4090, 21 days ago

(sqrt(cos(x))*cos(400*x)+sqrt(abs(x))-0.4)*(4-x*x)^0.1

Answers

Answered by ft46bmqzjs
0

Answer:

Step-by-step explanation:

Answered by kumark54321
0

Answer:

The distance between two points on a curve's section is known as the arc length.

Arc Length=∫ba√1+[f′(x)]²dx.

Step-by-step explanation:

What is meant by arc length integral?

Arc Length=∫ba√1+[f′(x)]²dx.

We must ensure that f′(x) is an integrable expression because we are integrating an expression that contains f′(x).

A line integral integrates x and y functions over the line s after combining two dimensions into s, which is the total of all the arc lengths that the line makes.

The distance between two points on a curve's section is known as the arc length. Curve rectification is the process of estimating the length of an irregular arc segment by treating the segment as a collection of connected line segments. The number of segments in the rectification of a rectifiable curve is finite.

Let the given equation be

(sqrt(cos(x)) × cos(400 × x) + sqrt(abs(x)) - 0.4) × (4-x × x)^0.1

Then the arc length integral exists

$$\begin{aligned}& \int_{-4.5}^{4.5} \sqrt{\left(-\frac{2 x^2}{-9+x^2}+\right.}  \left(-\frac{0.02 x\left(-0.7+\sqrt[4]{x^2}+\sqrt{\cos (x)} \cos (200 x)\right)}{\left(4-x^2\right)^{0.99}}+\frac{1}{2}\left(4-x^2\right)^{0.01}\right. \\& \left.\left.\left(\frac{x}{\left(x^2\right)^{3 / 4}}-\frac{\cos (200 x) \sin (x)}{\sqrt{\cos (x)}}-400 \sqrt{\cos (x)} \sin (200 x)\right)\right)^2\right) d x \\&\end{aligned}$$

The complete question is:

(sqrt(cos(x))*cos(200x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5

To learn more about integrable expression refer to:

https://brainly.in/question/32454528

https://brainly.in/question/1096099

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