square of 3 x minus 4 Y
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Answered by
13
(3x - 4y ) ^ 2
= (3x)^2 + (-4y)^2 + 2*3x*4y
=9(X)^2 + 16(y)^2 + 24xy.
therefore the answer = 9x^2+16y^2+24xy..
hope helps uhhhh
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Answered by
7
See required product=(3x-4y)2
So identity used is (a-b)2 =a2+2(a)(b)+b2
(3x-4y)2=(3x)2+2(3x)(4y)+(4y)2
= (9x)2+2(12xy)+(16y)2
=(9x)2+24xy+(16y)2
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