Square of f is continuous functions proof in analysis
Answers
Answered by
0
Answer:
Step-by-step explanation:
Prove that if f is defined for x≥0 by f(x)=x−−√, then f is continuous at every point of its domain.
Definition of a continuous function is:
Let A⊆R and let f:A→R. Denote c∈A.
Then f(x) is continuous at c iff for every ε>0, ∃ δ>0 such that
|x−c|<δ⟹|f(x)−f(c)|<ε.
My attempt:
We know that the function f:x→R, where x∈[0,∞) is defined to be f(x)=x−−√. So, for 0≤x<∞, then |f(x)−f(c)|=|x−−√−f(c)| and I can't continue since I don't necessarily know what c is in this case.
Similar questions