Math, asked by jaswantu8462, 9 months ago

Square of (tan A + Cot A )

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Answered by nigamsoni014

0

Answer: (tan A + Cot A )^2

= tan^2 A + cot^2A +2*tan A* cot A

= tan^2 A + cot^2A +2*tan A* 1/tan A

= tan^2 A + cot^2A +2

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