Find the natural root of the following qudrantic equation if the real roots are exist 1) 6x²=x+1
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Step-by-step explanation:
6x²=x+1
=>6x²-x-1=0
=>6x²-3x+2x-1=0
=>3x(2x-1)+1(2x-1)=0
=>(3x+1)(2x-1)=0
=>3x+1=0 or 2x-1=0
=>x=-1/3 or x=1/2
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