square of
rashmiriddh1704:
please let me know the answer
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Using the identity:-
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
a=5
b=-y
c=-5
=5²+(-y)²+(-5)²+2(5×(-y))+2(-y×(-5))+2(-5×5)
=25+y²+25-10y+10y-50
=25+25-50-10y+10y+y²
=50-50+y²
=0+y²
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