Question

Square pyramidal MX4 molecule belongs to C4v point group and symmetry elements are E, 2C4, C2, 2σv, 2σd the trace for the reducible representation is-
a) 5 1 1 1 3
b) 5 1 1 1 1
c) 1 1 1 1 1
d) 4 1 1 1 3

Answer 1

Answer:

511113 this is the answer in this question ❓⁉️

Answer 2

SQUARE PYRAMIDAL

Explanation ;

     E ;

             Here operation E means identity operation . when we operate  

           identity the whole molecule remain same . so here no of atoms      intact is 5 .

  2C4 ;

           The C4(rotation of 90 degree) axis will  be perpendicular to the molecule and through the metal center  . As the molecule here rotated by 90 degree only the metal center remain intact . So here the no of atoms unaltered is 1 .

 C2 ;

        The C2( rotation of 180 degree) axis will be in the same position as C4 . So here also 1 atom (metal center) will be unaltered i.e. no of atom unaltered is 1 .

sigma (v) ; 

        by this operation no of atoms unaltered  is 1 .

sigma (d) ;

     So here the no of atoms unaltered is 3 .

    The Reducible representation will be 51113