Math, asked by chinMaya007, 5 months ago

square root of 128 - square root of 98 + square root of 18 ​

Answers

Answered by yuvrajsinghthd747
1

Answer:

 \sqrt{128}  = 8 \sqrt{2}  \\  \sqrt{98}  = 7 \sqrt{2 }  \\  \sqrt{18}  = 3 \sqrt{2}  \\   \\ 8 \sqrt{2}  - 7 \sqrt{2}  + 3 \sqrt{2}  \\  = 5.65 \\  \\ hope \: this \: will \: help \: you

Answered by kumarnavdep949
0

Step-by-step explanation:

firstly we,

done square roots for all given no.'s

after this we find

square root of 128= 16 , 98=14,18=6

after we do 16-14+6 that was given in question

16-14=2

2+6

8

I don't sure this is correct answer or not

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