square root of 7+2√10
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Answered by
22
We have to find the square root of 7+2root10
Now,
Root 7+2root10
= root of 2+5+2root10
= root of (root 2)^2 + (root 5)^2 + 2*root2*root5
= root of ( root 2 + root 5 )^2
= root 2 + root 5
Now,
Root 7+2root10
= root of 2+5+2root10
= root of (root 2)^2 + (root 5)^2 + 2*root2*root5
= root of ( root 2 + root 5 )^2
= root 2 + root 5
Answered by
42
Hey Dear !!!
This is your answer..
We have to obtain the Square Root of 7+2√10.
Keep in mind that (√a)² = aSo, ⇒ 7 + 2√10⇒ 2 + 5 + 2√10⇒ (√2)² + (√5)² + 2 × √2 × √5
Now, using a² + b² + 2ab = (a+b)²⇒ (√2)² + (√5)² + 2 × √2 × √5 = (√2 + √5)²⇒ Now Square Root of (√2 + √5)² = (√2 + √5)
Hope It Helps
This is your answer..
We have to obtain the Square Root of 7+2√10.
Keep in mind that (√a)² = aSo, ⇒ 7 + 2√10⇒ 2 + 5 + 2√10⇒ (√2)² + (√5)² + 2 × √2 × √5
Now, using a² + b² + 2ab = (a+b)²⇒ (√2)² + (√5)² + 2 × √2 × √5 = (√2 + √5)²⇒ Now Square Root of (√2 + √5)² = (√2 + √5)
Hope It Helps
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