square root of
L^2*T^-2
Answers
Answered by
0
Answer:
g=4π2LT2gExplanation:
First,
what you want to do is square both sides of the equation to get rid of the square root, since squaring a number is the inverse of taking the square root of a number:
T
2
=
(
2
π
)
2
√
(
L
g
)
2
T
2
=
(
2
π
)
2
(
L
g
)
second,
we simplify the
(
2
π
)
2
part so it's easier to read. Remember, when you square something in parenthesis, you are squaring every single term inside:
T
2
=
4
π
2
(
L
g
)
third,
multiply both sides by
g
:
g
×
T
2
=
4
π
2
(
L
g
)
×
g
g
×
T
2
=
4
π
2
L
finally,
divide both sides by
T
2
to get
g
by itself:
g
×
T
2
T
2
=
4
π
2
L
T
2
Thus,
g
is equal to:
g
=
4
π
2
L
T
2
Similar questions