square root of x÷y +square root of y÷x = 10÷3 . Find xy
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Hello,
√(x/y) + √(y/x) = 10/3
√(x/y) = 10/3 - √(y/x)
x/y = (10/3 - √(y/x))^2
x/y = y/x + 100/9 - (20/3)√(y/x)
x/y - y/x = 100/9 - (20/3)√(y/x)
x^2 - y^2 = xy(100/9 - 20√(y/x)/3)
Integer solutions:
x = -9, y = -1
x = -1, y = -9
x = 1, y = 9
x = 9, y = 1
xy = 9
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