Question

Srivani walks 12m due East and turns left and walks another 5m, how far is she from the place started?

Answer 1

First he cover 12 m east then turn left or move toward north and walk 5 m. After this the displacement or the shortest distance between she and the final point is
$\sqrt{12 { }^{2} { + 5}^{2} }$
So the anwer is 13

Answer 2

Answer:

13m

Step-by-step explanation:

Refer the attached figure.

Srivani walks 12 m due East i.e. AB = 12 m

Then after turning left she walks 5 m i.e.BC = 5 m

Now we are supposed to find how far is she from the place started i.e. Length of AC

So, we will use Pythagoras theorem :

$Hypotenuse^2=Perpendicular^2+Base^2$

$AC^2=BC^2+AB^2$

$AC^2=5^2+12^2$

$AC^2=25+144$

$AC^2=169$

$AC=13m$

Thus she is 13 m away from the place started.