Question

SSC Test Questions

The volume of a vessel containing an ideal gas is doubled and its temperature (in °K) is also doubled. The pressure of the gas -

Answer 1

Let,
P₁ be the initial pressure
P₂ be the final pressure 
V₁ be the initial volume
V₂ be the final volume = 2(V₁)
T₁ be the initial temperature
and T₂ be the final temperature = 2(T₁)

PV / T = constant 

⇒P₁V / T₁ = P₂V₂ / T₂
⇒P₁V₁ / T₁ = P₂ × 2(V₁) / 2(T₁)
⇒P₁ = P₂

So, the pressure of the gas remains the same.